1^2(4x-10)+5=x-11

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Solution for 1^2(4x-10)+5=x-11 equation: 



1^2(4x-10)+5=x-11

We move all terms to the left:

1^2(4x-10)+5-(x-11)=0

We get rid of parentheses

1^2(4x-10)-x+11+5=0

We add all the numbers together, and all the variables

-1x+1^2(4x-10)+16=0

We move all terms containing x to the left, all other terms to the right

-1x+1^2(4x-10)=-16

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